if 6a+b2=97,where A and B are the digit ,then the values of A and B respectively are
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Given : 6A + B2 = 97
A and B are the digit
To Find : values of A and B
Solution:
6A + B2 = 97
6A = 6 x 10 + A = 60 + A
B2 = 10 x B + 2 = 10B + 2
60 + A + 10B + 2 = 97
=> 10B + A = 35
=> 10B + A = 10 x 3 + 5
=> B = 3
A = 5
6A + B2 = 97
=> 65 + 32 = 97
A = 5
B = 3
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