Question

If 6cos^-1(x² - 4x√3/2 =π , what is the valued of X.​

Answer 1

Answer:

sin

−1

(x)ϵ[−1,1]

Therefore

−1≤x

2

−4x+6≤1

−1≤(x−2)

2

−4+6≤1

−1≤(x−2)

2

+2≤1

−3≤(x−2)

2

≤−1

Now, (x−2)

2

>0 for all xϵR.

Hence the inequality

−3≤(x−2)

2

≤−1 yields no real real values of x.

Therefore,

∣x

2

−4x+6∣ cannot be less than or equal to 1.

Hence sin

−1

(x

2

−4x+6) is no possible.

The, same goes for cosx.

Hence the answer is none of these