If 6th and 10th terms of an A.P. are -10 and -26 respectively, then its 15th term will be
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a+5d=-10......equation 1
a+9d =-26 .....equation 2
Subtract equation 1 from equation 2
a+9d-a-5d -26+10
4d = -16
d = -4
Putting the value of d in equation 1
a+5(-4)=-10
a = 10
15th term
a+14d
10+14(-4)
10-56
-46
Hope it helps you plz mark as brilliant answer
a+9d =-26 .....equation 2
Subtract equation 1 from equation 2
a+9d-a-5d -26+10
4d = -16
d = -4
Putting the value of d in equation 1
a+5(-4)=-10
a = 10
15th term
a+14d
10+14(-4)
10-56
-46
Hope it helps you plz mark as brilliant answer
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