If 6th and 12th terms of an
a.P are 13 and 25 ,then its first term is-
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Answered by
1
6th term = 13
12th term= 25
we can write the 6th term as
a+5d=13
and
12th term as
a+11d=25
subtracting equation 2 from 1
we get Common difference
D=2
putting the value of D in equation1 we get a+5*2=13
a= 13-10=3
therefore the first term A =3
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12th term= 25
we can write the 6th term as
a+5d=13
and
12th term as
a+11d=25
subtracting equation 2 from 1
we get Common difference
D=2
putting the value of D in equation1 we get a+5*2=13
a= 13-10=3
therefore the first term A =3
hope it helps you
mark it as brainliest if helpful
Anonymous:
thanks
Answered by
0
here given that t6 = 13 and t12 = 25.
and we know that tn = a+ ( n-1) d
putting their values
13= a + (12)d. 1
and
25= a+(24)d . 2
from equation 1 and 2
we get
a = - 46.
and D = 11/12.
but this question is wrong because D never comes in fraction..
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