Question

If 6x =sec theta and 6/x=tan theta, find the value of 9(x2 -1/x2)

Answer 1

= (18 Xsq × 18)÷X

I hope it helps

Answer 2

6x=secA

or, x=secA/6

or, x²=sec²A/36

and 6/x=tanA

or, 1/x=tanA/6

or, 1/x²=tan²A/36

9(x²-1/x²)=9(sec²A/36-tan²A/36)=9(sec²A-tan²A)/36=9/36=1/4;

(∵, sec²A-tan²A=1)

Hope u'll understand it.. Thanks