if 6x=sec theta and6/x = tan theata find value of 9(xsquare-1/xsquare)
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the above is the answer of your question as I am a expert teacher at a school in london
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6x=sec theta, 6/x=tan theta
=> x=sec theta/6 => 1/x=tan theta /6
=> xsq=sec^2 theta /36 => 1/xsq=tan^2 theta/36
putting this value of x^2 and 1/x^2 in the given eq
=> 9(sec^2 theta /36 - tan^2 theta/36) (sec^2 theta-tan^ theta=1)
= 9*1/36
= 1/4_________ans
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