if 6x=secA and 6/x=tanA find 9(x²-1/x²)
Answers
Answered by
1
sec^2(A)- tan^2(B) = 1
36x^2 - 36/x^2 = 1
36(x^2- 1/x^2) = 1
4×9(x^2 -1/x^2) = 1
9(x^2 -1/x^2)= 1/4
36x^2 - 36/x^2 = 1
36(x^2- 1/x^2) = 1
4×9(x^2 -1/x^2) = 1
9(x^2 -1/x^2)= 1/4
Similar questions