Question

If 6x=sectheta and 6/x=tantheta find the value of 9(x²-1/x²)
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Answer 1

Answer:

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Step-by-step explanation:

now here 6x=sec theta

and 6/x=tan theta

thus x=sec theta/6

1/x=tan theta/6

so substituting these values in 9(x²-1/x²)

we get

9[(sec theta/6) square-(tan theta/6)square]

ie 9(sec square theta/36-tan square theta/36)

=9(sec square theta-tan square theta/36)

so we know that

sec square theta-tan square theta=1

thus then

9×1/36

=1/4

=0.25