Math, asked by jidma1911, 10 months ago

Q2. 1000 tickets were sold. Adult tickets cost $85, children's cost $45, and a total of $7300 was collected. How many tickets of each kind were sold? Hint: Let x be the number of adult tickets. Let y be the number of children's tickets. By using Matrix Inversion Method and Cramer’s Rule.

Answers

Answered by Anonymous
16

Children = 300

a = Adult

c = Children

Then- a + c

= 1000 ---------------------------(1)

8.50

a + 4.50

c = 7300 -----------(2)

Solve the equation (1) for c

c = 1000 − a

Substitute the value of c in equation (2)

8.50

a + 4.50 ( 1000 − a ) = 7300

8.50

a + 4500

4.50

a

)

=

7300

4

a

=

7300

4500

=

2800

a

=

2800

4

=

700

Substitute the value of a in equation (1)

700

+

c

=

1000

c

=

1000

700

=

300

Answered by Anonymous
3

Answer:

1000 tickets were sold. Adult tickets cost $85, children's cost $45, and a total of $7300 was collected. How many tickets of each kind were sold? Hint: Let x be the number of adult tickets. Let y be the number of children's tickets. By using Matrix Inversion Method and Cramer’s Rule.

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