Question

If 7^2x+1÷49=343,find the value of ×

Answer 1

$\frac{ {7}^{2x + 1} }{49} = 343$

$\frac{ {7}^{2x + 1} }{ {7}^{2} } = {7}^{3}$

${7}^{2x + 1} = {7}^{3} \times {7}^{2}$

${7}^{2x + 1} = {7}^{5}$

$2x + 1 = 5$

$2x = 4$

$x = 2$

$hope \: it \: helps$