if 7^3 2^7 and 9^3 are factors of a number denoted by (a*2^6*91*81) then what is the smallest possible value of 'a'?
Answers
Answer:882
Step-by-step explanation:
(a*(2^6)*7*23*(3^4)) / (7^2)*(2^7)*(3*6)
by solving this we can
Given :- if 7^3 2^7 and 9^3 are factors of a number denoted by (a*2^6*91*81) then what is the smallest possible value of 'a' ?
Solution :-
lets see prime factors of given number :-
→ a * 2⁶ * 91 * 81
→ a * 2⁶ * 7 * 13 * 9²
Now, we have given that, 7^3 , 2^7 and 9^3 are factors of given number.
to need least value of a , let us assume that, quotient is 1 .
Than,
→ (7³ * 2⁷ * 9³) * 1 = a * 2⁶ * 7 * 13 * 9²
now, as we can see :-
- if 7³ divide RHS completely, we need 7² .
- if 2⁷ divide RHS completely, we need 2.
- if 9³ divides RHS completely, we need 9 .
therefore,
→ Least value of a = 7² * 2 * 9 = 49 * 18 = 882 (Ans.)
Hence, Least value of a is 882.
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