if (7,a),(-5,2),(3,6) are points on the straight line find the value of a
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Solution
if line is straight
The points are Colliner.
so, it area = 0
=> 1/2 [7 (2-6)+(-5)(6-a)+3 (a-2)] =0
=> -28 - 30 + 5a + 3a - 6 =0
=> 8a = 64
=> a = 8
_____________
Hope it helps
#Amrit⭐
if line is straight
The points are Colliner.
so, it area = 0
=> 1/2 [7 (2-6)+(-5)(6-a)+3 (a-2)] =0
=> -28 - 30 + 5a + 3a - 6 =0
=> 8a = 64
=> a = 8
_____________
Hope it helps
#Amrit⭐
pranavnagmote:
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