Which equation represents a circle with a center at (–3, –5) and a radius of 6 units? (x – 3)2 + (y – 5)2 = 6 (x – 3)2 + (y – 5)2 = 36 (x + 3)2 + (y + 5)2 = 6 (x + 3)2 + (y + 5)2 = 36
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The general equation of a circle is:
(x - a)² + (y - b)² = r²
Where:
The centre is (a, b) and the radius = r
For a circle center at (–3, –5) and a radius of 6 units, the equation will therefore be:
(x + 3)² + (y + 5)² = 6²
(x + 3)² + (y + 5)² = 36
(x - a)² + (y - b)² = r²
Where:
The centre is (a, b) and the radius = r
For a circle center at (–3, –5) and a radius of 6 units, the equation will therefore be:
(x + 3)² + (y + 5)² = 6²
(x + 3)² + (y + 5)² = 36
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2
Answer:
Step-by-step explanation:
The general equation of a circle is:
(x - a)² + (y - b)² = r²
Where:
The centre is (a, b) and the radius = r
For a circle center at (–3, –5) and a radius of 6 units, the equation will therefore be:
(x + 3)² + (y + 5)² = 6²
(x + 3)² + (y + 5)² = 36
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