# if 7 is subtraced from 5 times a number, answer is 35 more than twice the number

## Answers

Answered by

0

**Answer:**

L.H.S. = x2 – y2

= (p sec θ + q tan θ)2 – (p tan θ + q sec θ)2

= p2 sec θ + q2 tan2 θ + 2 pq sec 2 tan 2 -(p2 tan2 θ + q2 sec2 θ + 2pq sec θ tan θ)

= p2 sec θ + 2 tan2 θ + 2pq sec θ tan θ – p2 tan2 θ – q2 sec θ – 2pq sec θ tan θ

= p2(sec2 θ – tan2 θ) – q2(sec?2 θ – tan2 θ) =

= p2 – q2 …[sec2 θ – tan2 θ = 1

= R.H.S.hii

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Answered by

1

**Answer:**

**Step-by-step explanation:**

Let number is X.

Then two time of number is 2x.

7time of number is 7x.

Subtraction is 2x-7x = 5 ……(1)

-5x = 5.

X = 5/-5 = -1

X = -1.

Verification.

Taking the value of X in equation (1)

2(-1) -7(-1)

-2+7= 5.

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