Question

If 7 is subtracted from five times a number, the result is 63. Find the number
1 point
Required number = 20
Required number =14
Required number =36
None of these

Answer 1

Let us assume:

• The required number be x.

Given:

• 7 is subtracted from five times a number, the result is 63.

Finding the required number:

According to the question.

↠ 5x - 7 = 63

↠ 5x - 7 = 70 - 7 [∵ 70 - 7 = 63]

Cancelling 7 both sides.

↠ 5x = 70

↠ 5x = 5(14) [∵ 5(14) = 70]

Cancelling 5 both sides.

↠ x = 14

Hence,

• The required number be 14.

Answer 2

Question given:

• If 7 is subtracted from five times a number, the result is 63. Find the number

Information provided with us:

• 7 is subtracted from 5 times a number.
• Result of that subtraction is 63

What we have to calculate:

• We have to calculate the number

How to solve:

• These type of questions are of linear equations. First of all we have to assume a number be any variable eg, x or y. Then set-up an equation in terms of information given.

Assumptions needed inorder to solve:

• Here we would be assuming the number be y from which 7 is subtracted of its five times.

Let's start:

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ______________

5 times a number:

• Multiplying the assumed variable with 5.

$: \longmapsto \: \tt{number \: = \: 5 \: \times \: y}$

$: \longmapsto \: \tt{number \: = \: 5 y}$

7 is subtracted:

$: \longmapsto \: \tt{number \: = \: 5y - 7}$

Result is 63:

$: \longmapsto \: \red{\boxed{\tt{ \: 5y - 7 \: = \: 63}}}$

It's the equation formed.

Transposing 7 to R.H.S. it would be positive,

$: \implies \: \tt{5y \: = \: 63 + 7}$

$: \implies \: \tt{5y \: = \: 70}$

Dividing 70 by 5,

$: \implies \: \tt{y \: = \: \dfrac{70}{5} }$

$: \implies \: \tt{y \: = \: \cancel\dfrac{70}{5} }$

$: \implies \: \red{\boxed{\tt{y \: = \: 14}}}$

Conclusion:

• Number is 14