if 7 sin A -24 cos A =0, then find the value of of sec A.
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Answer:
given 7sinA-24cosA=0
7sinA=24cosA
sinA/cosA=24/7
tanA=24/7
we know sec^2 A- tan^2 A=1
sec^2 A - (24/7)^2=1
sec^2 A -576/49=1
sec^2 A =1+576/49
sec^2 A =625/49
sec^2 A=(25/7)^2
cancel powers
secA=25/7
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