Question

if 7 Sin square teta + 3 Cos square teta=4
Prive that sec teta+cosec teta=2+2/√3​

Answer 1

$\bf\large\underline\pink{Answer:-}$

2 MEANS SQUARE.

7 SIN2theta+3COS2theta=4

4SIN2theta+3SIN2theta+3COS2theta=4 (SIN2THETA+COS2THETA=1)

4SIN2theta+3=4

4SIN2theta=4-3

=1

SIN2theta=1/4

SINtheta=ROOT OF 1/4

SINtheta=SIN30 DEG. <SIN AND SIN GETS CANCELLED>

=1/2

SEC30DEG.+COSEC30DEG=1/ROOT3/2+1/1/2

=2+2/ROOT3

HENCE PROVED

<HOPE THIS WOULD HELP U>

Answer 2

Answer:

7 sin^2teta+ 3cos^2teta=4

4sin^2teta+(3sin^2teta+3cos^teta)

:(sin^2teta+cos^2teta) =1

then 4sin^2teta=1

sinteta=1/2

then pathagors rule

secretary=2/√3 and cosecteta = 2

so secteta + cosecteta =2+2/√3