Question

if 7 sin square theta + 3 cos square theta = 4 then show that tan theta = 1/root 3

Answer 1

$7 \sin {}^{2} \alpha + 3 \cos {}^{2} \alpha = 4 \times 1 \\ = > 7 \sin {}^{2} \alpha + 3 \cos {}^{2} \alpha = 4 \sin {}^{2} \alpha + 4 \cos { }^{2} \alpha \\ = > 3 \sin { }^{2} \alpha = \cos { }^{2} \alpha \\ = > \tan {}^{2} \alpha = 1 \div 3 \\ = > \tan \alpha = 1 \div \sqrt{3}$
HOPE THIS HELPS YOU!!!!