Question

If a2+b2+c2=1 and b+ic=(1+a)z then show a-ib/1+c=1+iz/1-iz

Answer 1

If b+ic= (1+a)z and a2 + b2 + c2 = 1 , then (1 + iz)/(1-iz) is equal to a) (a + ib )/(a-ib) b) (a-ib)/(1+c) c) (a +ib)/(1+c) d) (a-ib)/( 1-c)