Question

if 7 sin²∅ + 3cos²∅= 4 , find the value of sec∅ + cosec∅​

Answer 1

Step-by-step explanation:

hope it's help to u............................

Answer 2

Answer:

7sin²A + 3cos²A = 4

7sin²A + 3( 1 - sin²A) = 4

7sin²A + 3 - 3sin²A = 4

4sin²A = 1

sin²A = 1/4

sin A = 1/√2 = sin 30°

=> A = 30°

So, sec A = 1/cos A = 1/cos 30° = 2/√3

And, cosec A = 1/sin A = 1/sin 30° = 2

So answer will be

$\frac{2}{ \sqrt{3} } + 2 \\ = \frac{2 + 2 \sqrt{3} }{ \sqrt{3 } } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ = \frac{2 \sqrt{3} + 6 }{3} \\ answer \: = \frac{6 + 2 \sqrt{3} }{3}$

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