if 7 times of 7 term of AP is equal to 11 times the 11th term then its 18term will be will be
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Hey friend,
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Let the first term be a and common difference be d.
T₇ = a + (7-1)d
= a + 6d
7 * T₇ = 7*(a+6d)
= 7a + 42d ------------------------(i)
T₁₁ = a + (11-1)d
= a + 10d
11 * T₁₁ = 11*(a +10d)
= 11a + 110d ------------------------(ii)
(i) = (ii)
7a + 42d = 11a + 110d
4a = 68d
a = 17d
T₁₈ = a + (18-1)d
= a + 17d
= 17d + 17d {a = 17d}
= 34d
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Hope this helped you !!
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