Question

if 7128 equal to 2 to the power p × 3 to the power q × 11 to the power r find pqr

Answer 1

According to question,

$7128 = {2}^{p} {3}^{q} {11}^{r}$

Lets split 7128 into its factor

$7128 = 2 \times 3564 \\ 3564 = 2 \times 1782 \\ 1782 = 2 \times 891 \\ 891 = 3 \times 297 \\ 297 = 3 \times 99 \\ 99 = 3 \times33 \\ 33 = 3 \times 11$

So,

$7128 = {2}^{3} {3}^{4} {11}^{1}$

So,

p=3

q=4

r=1

so, pqr=12

Hope it helps you

Answer 2

Answer:

According to question,

7128 = {2}^{p} {3}^{q} {11}^{r}7128=2

p

3

q

11

r

Lets split 7128 into its factor

\begin{gathered}7128 = 2 \times 3564 \\ 3564 = 2 \times 1782 \\ 1782 = 2 \times 891 \\ 891 = 3 \times 297 \\ 297 = 3 \times 99 \\ 99 = 3 \times33 \\ 33 = 3 \times 11\end{gathered}

7128=2×3564

3564=2×1782

1782=2×891

891=3×297

297=3×99

99=3×33

33=3×11

So,

7128 = {2}^{3} {3}^{4} {11}^{1}7128=2

3

3

4

11

1

So,

p=3

q=4

r=1

so, pqr=12

Hope it helps you