if 713z is dividible by 5 find the value of z
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if z=5,then 7135/5 is 1427 and if z=0,then 7130/5 is 1426.So z can be either 0 or 5
kavi6:
give proper solution
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firstly,there is no such word as dividible. the word is divisible.
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it can either be 0 or 5 because
7135 is divisible by 5 and 7130 is also divisible by 5 (5 can be divided by any number having 5 or 0 at unit's place)
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it can either be 0 or 5 because
7135 is divisible by 5 and 7130 is also divisible by 5 (5 can be divided by any number having 5 or 0 at unit's place)
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