if 7a +i(3a - b) =21 - 3i then find a & b
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Given : 7a + i (3a-b) = 21- 3i
To Find : value of a and b
Solution:
7a + i (3a-b) = 21- 3i
p + qi = r + is
=> p = r and q = s
Hence equating real part with real and imaginary part with imaginary
7a = 21
=> a = 3
3a-b = - 3
Substitute a = 3
=> 3(3) - b = - 3
=> 9 - b = - 3
=> -b = - 12
=> b = 12
Hence Values of a and b are 3 and 12 respectively
a = 3
b = 12
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