If 7sin 2 theta + 3cos 2 theta =4 then prove that sec thetha +cosec theta= 2+2/root 3
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Answered by
102
2 MEANS SQUARE.
7 SIN2theta+3COS2theta=4
4SIN2theta+3SIN2theta+3COS2theta=4 (SIN2THETA+COS2THETA=1)
4SIN2theta+3=4
4SIN2theta=4-3
=1
SIN2theta=1/4
SINtheta=ROOT OF 1/4
SINtheta=SIN30 DEG. <SIN AND SIN GETS CANCELLED>
=1/2
SEC30DEG.+COSEC30DEG=1/ROOT3/2+1/1/2
=2+2/ROOT3
HENCE PROVED
<HOPE THIS WOULD HELP U>
7 SIN2theta+3COS2theta=4
4SIN2theta+3SIN2theta+3COS2theta=4 (SIN2THETA+COS2THETA=1)
4SIN2theta+3=4
4SIN2theta=4-3
=1
SIN2theta=1/4
SINtheta=ROOT OF 1/4
SINtheta=SIN30 DEG. <SIN AND SIN GETS CANCELLED>
=1/2
SEC30DEG.+COSEC30DEG=1/ROOT3/2+1/1/2
=2+2/ROOT3
HENCE PROVED
<HOPE THIS WOULD HELP U>
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