If 7sin²∅ + 3cos²∅ = 4
Then prove tan∅ = 1/√3
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Hey dear!!
Here's your answer
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7 tan²α + 3 = 4 sec²α
7 tan²α + 3 = 4 + 4 tan²α
3 tan²α = 1
tan α = 1/√3
Here's your answer
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7 tan²α + 3 = 4 sec²α
7 tan²α + 3 = 4 + 4 tan²α
3 tan²α = 1
tan α = 1/√3
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