Question

The diameter of a roller is 110cm and its length is 140cm. Find the area levelled by it in 500 revolutions .

Answer 1

Hi ,

Diameter of the roller ( d ) = 110 cm

Radius = r = d/2

r = 110/2 = 55 cm

Length of the roller = h = 140cm

Area levelled by one revolution

= Surface area of the roller ( cylinder )

= 2πrh

Area levelled by 500 revolution s

= 500 × 2πrh

= 500 × 2 × ( 22/7 ) × 55 × 140

= 1000 × 22 × 55 × 20

= 24200000 cm²

= 2420 m²

I hope this helps you.

:)

Answer 2

the diameter of roller =110 cm
length=140cm
to find CSA of cylinder for one revolution
radius =110÷2=55cm
22×55×55×140÷7=1331000 sq. cm
te take 500 revolution =1331000×500=665500000 sq. cm ÷10000=66550 sq. m