if 7sin2theta + 3 cos2theta = 4, then prove that sectheta + cosectheta = 2+2/root3
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7 sin^2theta+3 cos^2theta=4
7sin^2theta+3(1-sin^2theta)=4
7sin^2theta+3-3sin^2theta=4
4sin^2theta+3=4
4sin^2theta=1
sin^2theta=1/4
sin theta=+1/2
sin theta=+ pi/6
Therefore tan theta=+ pi/6
then we get tan theta= + 1/root 3
As the required answer us tan theta=+1/root 3(here we considered theta=+pi/6).
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