If 8 tan A=15,find (sinA-cosA).
Answers
Answered by
75
Tan A= 15/8=perpendicular/base
sinA=perpendicular/hypotenuse
cosA=Base/hypotenuse
(H)²=(P)²+(B)²
(H)²=(15)²+(8)²
(H)²=225+64
(H)²=289
H=17
sinA=15/17
cosA=8/17
sinA-cosA=15/17-8/17
15-8/17
→ 7/17
sinA=perpendicular/hypotenuse
cosA=Base/hypotenuse
(H)²=(P)²+(B)²
(H)²=(15)²+(8)²
(H)²=225+64
(H)²=289
H=17
sinA=15/17
cosA=8/17
sinA-cosA=15/17-8/17
15-8/17
→ 7/17
Answered by
29
SinA=15/17,CosA=8/17
(SinA-CosA)=(15/17)-(8/17)
. =15-8/17
. =7/17
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