Question

if 80% of the applications to a program were rejected, what is the ratio of the number accepted to the number rejected

Answer 1

Step-by-step explanation:

Let total no. of applications be x.

Applications rejected = 80x/100

Applications accepted = 20x/100 [100% - 80% = 20%]

Ratio = 20x/100 : 80x/100 = 1 : 4

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Answer 2

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Step-by-step explanation:let the total no of programs be 100

no of program rejected=80%of 100

                                         =80

no. of programs accepted=100-80=20

ratio=20:80

       =1:4

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