Chemistry, asked by saabujoseph, 1 year ago

If 80 volume of H2 (g) and 80 volume of O2 (g) react to form water under suitable condition then the limiting reagent is

1) H2. 2)O2
3)H2 and O2 both are limiting reagent
4) No reactant is limiting

Answers

Answered by Sidyandex
0

Mass of O2 =80gm ,Mass of H2 =80gm Molecular weight of O2= 32gm Molecular weight of Moles of H2 = 80/2=40 Moles of O2= 80/32=2.5

Here Oxygen is limiting reagent due to less moles available for reaction for 2.5 moles O2 required 5 moles of H and That is one mole O2 requires two moles of hydrogen.


tiwaavi: Its little wrong. Answer will be Hydrogen and Not Oxygen. Correct it.
tiwaavi: you're neither correcting nor responding. !!!
Answered by tiwaavi
4

Reaction for the H₂ and O₂ to form water is,

2H₂ + O₂ = 2H₂O

This means that 2 volume of Hydrogen requires 1 volume of Oxygen to form water.

Therefore,

80 volume of Oxygen requires 120 volume of Hydrogen to form water.

Therefore, Hydrogen is the Limiting Reagent.


Hope it helps.  

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