if 81^2x = 3^3x+ 125 find the value of 3x^2
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Given,
5
3x−1
÷25=125
Since, 25=5×5=5
2
And 125=5×5×5=5
3
Therefore given equation can be written as,
5
3x−1
÷(5)
2
=(5)
3
⇒(5)
3x−1−2
=(5)
3
[∵a
m
÷a
n
=(a)
m−n
]
⇒(5)
3x−3
=(5)
3
On comparing both sides, we get
⇒3x−3=3
⇒3x=6
⇒x=2
Hence, the value of x=2
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