If √81 + √48 + √75 – √108 = a + b √3, where a and b are rational numbers, find a and b.
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Answer:
A=9
B=3
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√81 + √48 + √75 – √108 = a + b√3
=> 9 + 4√3 + 5√3 - 6√3 = a+b√3
=> 9+3√3 = a+b√3
=> (9+3√3/√3) = a+b
=> a+b = 3+3√3
Both a and b are 3. Hence, a and b are rational number.
=> 9 + 4√3 + 5√3 - 6√3 = a+b√3
=> 9+3√3 = a+b√3
=> (9+3√3/√3) = a+b
=> a+b = 3+3√3
Both a and b are 3. Hence, a and b are rational number.
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