If 81^x = 9/3^x , find the value of x
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Given ( 81) ^x = 9/ 3^x
let us write 81 as 3*3*3*3 = 3^4 and 9 = 3*3 = 3^2
so it is now : ( 3^4)^x = 3^2 / 3^x
3^4x = 3^(2-x)
as both sides have same base the exponent should also be same
4x = 2-x
adding x both sides 4x + x = 2
5x = 2
x= 2/5
Answer 2/5
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