Question

if (81)^y=1/(27)^x, then the value of x in terms of y is ?​

Answer 1

Answer:

$x = \frac{ - 4y}{3}$

Step-by-step explanation:

(81)^y = 1/(27)^x

((3)^4)^y = ((3)^(-3))^x

(3)^4y = (3)^(-3x)

Since bases are same therefore exponents are equal

4y = -3x

-3x = 4y

x = -4y/3