Question

If 8947A56B1 is divided by 9 where B is an odd number. Find the sum of all possible value of A.

Answer 1

Answer:

If n is divisible by 9 then sum of all digits should be divisible by 9.

then,

8+9+4+7+A+5+6+B+1 should be divisible by 9

40+A+B should be divisible by 9

if B=1 then 41+A should be divisible by 9

so A=4, because 45 is divisible by 9

if B=3 then 43+A should be divisible by 9

so A=2

if B=5 then 45+A should be divisible by 9

so A=0,9

if B=7 then 47+A should be divisible by 9

so A=7

if B=9 then 49+A should be divisible by 9

so A=5

now, Addition of all values of A

4,2,0,9,7,5 are all possible values of A

so,

4+2+0+9+7+5 = 27

Hope it helps