Chemistry, asked by pravinb27, 1 year ago

If 8g NaOH is dissolved in 1L of solution,its molarity is:-

Answers

Answered by ayuugupta30
7
0.2 M
As M = moles/volume
Therefore, 8÷40/1
1÷5 =. 0.2 M
Answered by BrainlySmile
1

Answer- The above question is from the chapter 'Some Basic Concepts of Chemistry'.

Molarity: Number of moles of solute present in 1 litre of solution is called molarity.

Unit of Molarity = Molar (M)

•Number of moles = Given mass/Gram atomic/molecular mass

•When volume is given in litres,

Molarity = No. of moles of solute ÷ Volume of solution in litres

•When volume is given in millilitres,

Molarity = (No. of moles of solute × 1000) ÷ Volume of solution in ml

Given question: If 8 g NaOH is dissolved in 1 L of solution, its molarity is:-

(Atomic masses of Na = 23, O = 16 and H = 1)

Solution: Given mass of NaOH = 8 g

Gram molecular mass of NaOH = 1[Na] + 1[O] + 1[H] = 23 + 16 + 1 = 40 g

Number of moles of NaOH = Given mass/Gram atomic/molecular mass

                                               = 8/40 = 1/5 = 0.2 moles

Volume = 1 litre

Molarity = No. of moles of solute ÷ Volume of solution in litres

∴ Molarity = 0.2/1 = 02 Molar or 0.2 M

∴ If 8 g NaOH is dissolved in 1 L of solution, its molarity is 0.2 M.

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