Question

if 8tan theeta -15=0 , then find sin theeta -cos theeta
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Answer 1

Answer:$=Theeta

sin(90-8$)=sin$

90-8$=$

90=$+8$

9$=90

$=10

So,

tan3$ = tan(3×10)

= tan(30)

=1/underroot3

Step-by-step explanation:

Answer 2

Answer:

8 tan theeta= 15

tan theeta =15/8

therefore h=√161

sin theta= 15 √161

cos theta= 8/√161

sin -cos =(15-8)/√161

7/√161