If 8th term of an A. P is 0 prove that is 38th term is triple of its 18th term
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8th = a+(8-1)d = 0
a+7d = 0
)a = -7d(
We have to prove that,
18th * 3 = 38th term
(a+17d)*3 = a+37d
3a+51d = a+37d
Putting value of a
3*-7d + 51d = -7d+37d
-21d+51d = -7d+37d
30d = 30d
Hence proved.
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a+7d = 0
)a = -7d(
We have to prove that,
18th * 3 = 38th term
(a+17d)*3 = a+37d
3a+51d = a+37d
Putting value of a
3*-7d + 51d = -7d+37d
-21d+51d = -7d+37d
30d = 30d
Hence proved.
Plz Mark It As Brainliest Answer And Drop A ♥
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