Question

If (8x+1) , (6x-1) , (3x+5) are in A.P. Find x​

Answer 1

Answer:

x= 8

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Answer 2

The value of x is 8.

Step-by-step explanation:

Given : If (8x+1) , (6x-1) , (3x+5) are in A.P.

To find : The value of x ?

Solution :

In the A.P the difference between two consecutive term is same.

i.e. $a_2-a_1=a_3-a_2$

The A.P given is (8x+1) , (6x-1) , (3x+5).

Here, $a_1=(8x+1) , a_2=(6x-1) , a_3=(3x+5)$

$(6x-1)-(8x+1)=(3x+5)-(6x-1)$

$6x-1-8x-1=3x+5-6x+1$

$-2x-2=-3x+6$

$x=8$

Therefore, the value of x is 8.

#Learn more

If the common difference is the A.P in which

T7=9 and T1.T2.T3 is least, is d Find d​

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