Question

If 9^× * 3^2 * (3^×/-2)^-2 = 1/27 ,Find x

Answer 1

Heya friend,
Here is the answer you were looking for:
${9}^{x} \times {3}^{2} ( {3}^{ \frac{x}{ - 2} } )^{ - 2} = \frac{1}{27} \\ \\ {(3}^{2} )^{x} \times {3}^{2} ( {3}^{ \frac{ - 2x}{ - 2} } ) = \frac{1}{ {3}^{3} } \\ \\ = {3}^{2x} \times {3}^{2} ( {3}^{x} ) = {3}^{ - 3} \\ \\ {3}^{ 2x } \times {3}^{2} \times {3}^{x} = {3}^{ - 3} \\ \\ {3}^{2x + 2 + x} = {3}^{ - 3} \\ \\ {3}^{3x + 2} = {3}^{ - 3}$

As the bases are same, so putting the powers equal:

$3x + 2 = - 3 \\ \\ 3x = - 3 - 2 \\ \\3x = - 5 \\ \\ x = - \frac{5}{3}$

If any doubt, please ask ;)

Thanks...
☺☺

Answer 2

Answer:

-5/3

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