Question

if 9×4=17,7×2=41,10×3=73, then 8×1 = ?

Answer 1

To get the answer, we need to analyze the given sequence.

 
[tex]9\times4=17 \\ 9^2-4^3=81-64=17 [/tex]


[tex]7\times2=41 \\ 7^2-2^3=49-8=41 [/tex]


[tex]10\times3=73 \\ 10^2-3^3=100-27=73 [/tex]


To get the number we are raising the 1st number to the power 2 and then subtracting the 2nd number raised to power 3.

 In $8\times1$, the 1st number is 8 and the 2nd number is 1.
Then, at first we need to raise 8 to the power of 2 and then subtract 1 raised to the power of 3.

$8\times 1=8^2-1^3=64-1=63$

Answer : 63

Answer 2

Answer:

Answer: Thank you so much you have explained very nicely