if 9 , 9and 8 =144 and 11,11 and 12 =192 then 10,10,and 11 are? Please send complete solution
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Answer:
174 is the required answer
Step-by-step explanation:
9, 9 and 8 = 144
So, 144 is obtained by :
Sum of all the digits = 9 + 9 + 8
= 26
Multiply by 6 = 26 × 6 = 156
Subtract 12 from the product = 156 - 12 = 144
11, 11 and 12 = 192
So, 192 is obtained by :
Sum of all the digits = 11 + 11 + 12
= 34
Multiply by 6 = 34 × 6 = 204
Subtract 12 from the product = 204 - 12 = 192
Similarly, for 10, 10 and 11
Sum = 10 + 10 + 11
= 31
Multiply by 6 = 31 × 6
= 186
Subtract 12 from it = 186 - 12
= 174
Hence, 174 is the required answer
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