Math, asked by smrithi1606, 5 months ago

If 9 and 41 are the smallest and largest numbers of a Pythagorean triplet, find the other number of the triplet.

Answers

Answered by Lucy0001

1

Answer:

other number=x

using pythagoras theorem,

$x^2=41^2 - 9^2= 1681- 81 =1600\\x=\sqrt{1600} =40$

Step-by-step explanation:

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