Question

if 9 and -5 are the zeroes of polynomial x^2+(a+5)x-b then find the value of a and b​

Answer 1

Answer:

a = -9 and b = 45

Step-by-step explanation:

α = 9

β = -5

Place α and β in -

==: x² + (a+5)x - b = 0

==: (9)² + (a+5) 9 - b = 0

==: 81 + 9a + 45 - b = 0

==: 126 + 9a - b = 0

==: 9a - b = -126  ........(1)

==: x² + (a+5)x - b = 0

==: (-5)² + (a+5) (-5) - b = 0

==: 25 - 5a - 25 - b = 0

==: 5a + b = 0    .......(2)

From 1 and 2 we get,

a = -9 and b = 45

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