if 9 and -5 are the zeroes of polynomial x^2+(a+5)x-b then find the value of a and b
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Answer:
a = -9 and b = 45
Step-by-step explanation:
α = 9
β = -5
Place α and β in -
==: x² + (a+5)x - b = 0
==: (9)² + (a+5) 9 - b = 0
==: 81 + 9a + 45 - b = 0
==: 126 + 9a - b = 0
==: 9a - b = -126 ........(1)
==: x² + (a+5)x - b = 0
==: (-5)² + (a+5) (-5) - b = 0
==: 25 - 5a - 25 - b = 0
==: 5a + b = 0 .......(2)
From 1 and 2 we get,
a = -9 and b = 45
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