Question

if 9 cm and 40 cm Are the two sides of the right triangle the it's hypothesis is=​

Answer 1

Answer:

41 cm

Step-by-step explanation:

By pythagoreas theorem we know that,

(AC) ²=(AB)²+(BC)²[where AC is the hypotenuse and AB and BC are the perpendicular and base]

So the hypotenuse of the given triangle will be-

(AC) ²=9²+40²

(AC) ²=81+1600

AC=√1681

AC=41

AC= hypotenuse=41

therefore the hypotenuse of the given triangle is 41cm

Answer 2

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CorrecT QuestioN :-

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If 9 cm and 40 cm are two sides of the right triangle then it's hypotenuse is?

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Given :-

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• The two sides of a right triangle are 9cm and 40 cm

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To Find :-

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• The hypotenuse of the triangle.

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SolutioN :-

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Formula used :-

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$\large \begin{gathered} { \boxed{ \underline{ \sf{ \purple{ {a}^{2} = {b}^{2} + {c}^{2} }}}}} \end{gathered}$

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$\qquad : \implies \sf{ {a}^{2} = {9}^{2} + {40}^{2} }$

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$\qquad : \implies \sf{ {a}^{2} = 81 + 1600 }$

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$\qquad : \implies \sf{ {a}^{2} = 1681}$

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$\qquad : \implies \sf{a = \sqrt{1681} }$

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$\qquad : \implies \sf{a = }41$

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$\large \begin{gathered}{ \boxed { \underline{ \sf{ \orange{Therefore, \: the \: hypotenuse \: is \: 41cm}}}}} \end{gathered}$

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