Question

If √9-(n-2)×(n-2) is a real number , then the number of integral values of n is

Answer 1

Step-by-step explanation:

$\sqrt{9-(n-2)^2}<=R$

$9-(n-2)^2\geq 0$

⇒$(n-2)^2-9\leq 0$

⇒$(n-2)^2-3^2\leq 0$

⇒$(n-2+3)(n-2-3)\leq 0$

⇒$(n+1)(n+5)\leq 0$

$n<-[-1,5]$

$n=-1,0,1,2,3,4,5$

Answer:

C) 7

Answer 2

Answer:

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