If 9^n × 3²× (3^-n/2) –27 ÷ 3^3m × 2³ = 1/27
Prove that m–n= 1
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9∧n*3²*(3∧-n/2)-27/3∧3m*2∧3=1/27
3∧2n*3²*(3∧-n/2)-3³/3∧3m*2∧3=1/27
3∧2n+2-n/2-3³/3∧3m*2∧3=1/27
3∧3n+4 -33∧-3m=1/3∧3
3n+4-3m=1/3
⇒ m-n=1
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