Question

if 9 term an AP is 0 . proof that 29 term an AP is two times 19 term?​

Answer 1

Answer:

T9= a+(9-1)d=a+8d=0

T29=a+(29-1)d=a+28d =a+8d +20d =0+20d=20d

T19 =a+(19-1)d=a+18d=a+8d+10d=0+10d=10d

Therefore T29=2(T19)