if 9 times the 9th term of an A.P. is equak to 13times its 13th term, show that the 22th term of an A.P. is zero
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Answered by
0
Heya !!!
Given that,
9 ( 9th term ) = 13 ( 13th term )
9 ( A + 8D ) = 13 ( A + 12D)
9A + 72D = 13A + 156D
13A - 9A + 156D - 72D = 0
4A + 84D = 0
4A = -84D
A = (-84D/4) -------(1)
To prove :-
22 term = 0
=> A + 21D = 0
=> -84D/4 + 21D = 0
=> -84D + 84D/4 = 0
=> 0
HOPE IT WILL HELP YOU...... :-)
Given that,
9 ( 9th term ) = 13 ( 13th term )
9 ( A + 8D ) = 13 ( A + 12D)
9A + 72D = 13A + 156D
13A - 9A + 156D - 72D = 0
4A + 84D = 0
4A = -84D
A = (-84D/4) -------(1)
To prove :-
22 term = 0
=> A + 21D = 0
=> -84D/4 + 21D = 0
=> -84D + 84D/4 = 0
=> 0
HOPE IT WILL HELP YOU...... :-)
Answered by
3
Hello friend
Good morning
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To prove, 22th term = 0
Given that,
=>♠️ 9× 9th term = 13 × 13th term
=> ♠️9 x a + 8d = 13 x a + 12d
=>♠️ 9a + 72d = 13a + 156d
=>♠️13a - 9a = -156d + 72d
=>♠️4a = - 84d
=> ♠️a = - 21d
So A.T.Q
To prove 22th term = 0
So LHS = a + 21d
=>♠️LHS = - 21d + 21 d
=> ♠️LHS = 0 = RHS
Hence proved
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Good morning
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
To prove, 22th term = 0
Given that,
=>♠️ 9× 9th term = 13 × 13th term
=> ♠️9 x a + 8d = 13 x a + 12d
=>♠️ 9a + 72d = 13a + 156d
=>♠️13a - 9a = -156d + 72d
=>♠️4a = - 84d
=> ♠️a = - 21d
So A.T.Q
To prove 22th term = 0
So LHS = a + 21d
=>♠️LHS = - 21d + 21 d
=> ♠️LHS = 0 = RHS
Hence proved
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